Question

1.
The length of a rectangular wooden board is thrice its breadth. If the length of the
board is 120 cm, find the cost of framing it at the rate of 5 for 20 cm.​

Answer 1

$\huge{\underline{\overline{\bold{\mid{ANSWER:-}\mid}}}}$

$\large\underline{\underline{\mathtt{\red{Given:-}}}}$

Length of board is 120cm which is 3 times it's breadth then the breadth be

$\sf\implies \frac{1}{\cancel3}\times\cancel120\\ \\ \sf\implies 40cm$

Now :-

$\large\underline{\underline{\mathbb{\blue{ACCORDING\:TO\: QUESTION:-}}}}$

$\implies$The area of rectangle=Length ×breadth

Length= 120

breadth=40cm

Now :-..

Area = 120×40

Area of rectangle =>$\sf 4800cm{}^{2}$

The cost of 1 cm

$\sf\implies \frac{5}{20}\\ \\ \sf\implies\sf \frac{1}{4}$

Then the cost of framing:-

$\sf\longrightarrow \frac{1}{5}\times4800\\ \\ \sf\implies 960Rs.$

The cost of framing is ₹960

$\boxed{\underline{\red{\sf{Cost\:of\: framing=960Rs.}}}}$

Answer 2

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GIVEN,

♥️______

✨Length of board is 120cm which is 3 times it's breadth then the breadth be

$= > 1 \div 3 \times 120$

$= 40cm$

NOW,

$according \: \: to \: \: question$

The area of rectangle=Length ×breadth

$length =120$

$breadth = 40$

NOW,

$area \: of \: rectangle = 4800cm ^{2}$

$cost \: of \: 1 \: cm = 5 \div 20$

$= 1 \div 4$

$then \: cost \: of \: framing$

$= > 1 \div 5 \times 4800$

$= > 960$

$then \: cost \: of \: framing = 9600rs.$

▀▄ [_ANSWER_]▄▀

COST OF FRAMING =960 RS.

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