1. The length of a square with a circumference of 80 m is one meter greater than 2 times the width. See the length and width of the square?
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l= w - 2
w = w
area = l x w
area = (w-2) x w
= w^2 - 2w = 80
plug in to find solution
by trial and error
w = 10, check 10^2 - 2 x 10 = 100 - 20 = 80
l = 10 - 2
w = 10
l = 8
w = 10
l x w = area = 8 x 10 = 80. Another solution is to solve for roots of quadratic equation w^2 - 2w -80 = 0, (w -10)(w + 8) = 0. w - 10 = 0, w = 10 and w + 8 = 0, w = -8. There is no such thing as negative area so use positive root w = 10
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