1)
The length of one diagonal of a rombus
is less than the 2 diagonal by 4 Cm
The area of the rombus is 30 sg.cm
Find the length the of both the diagonal
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Answer:
area of rhombus=d1×d2/2
d1=x-4
d2=x
area=x(x-4) /2
area=x^2-4x/2
30×2=x^2-4
60+4=x^2
√64=x
x=8
d1=8-4=4cm
d2=x=8cm
hope iam current
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