Question

1. The length of the resistance wire is increased by 10%.
What is the corresponding change in the resistance of wire​

Answer 1

Answer : lf volume and density remains same, then resistance of wire . where l is length of the wire r= (1+10/100 1)r =11/10) square r

hence,r-r/r= 21/100 =21percent . therefore, chance in resistance of wire =21