Question

1. The lengths of the diagonals of a rhombus are
24 cm and 32 cm. The perimeter of the rhombus
[2010 (T-1)]
is :
​

Answer 1

Answer:

perimeter of the rhombus is 80 cm.

Step-by-step explanation:

# Given -

d1 = 24 cm

d2 = 32 cm

# Solution -

We know that diagonals of triangle intersect each other perpendicularly. So half of each diagonal forms a right angled triangle with side of rhombus as hypotenuse.

x^2 = (d1/2)^2 + (d2/2)^2

x^2 = (24/2)^2 + (32/2)^2

x^2 = 12^2 + 16^2

x^2 = 144 + 256

x^2 = 400

x = 20 cm

So perimeter of rhombus is -

Perimeter of rhombus = 4x

Perimeter of rhombus = 4 × 20

Perimeter of rhombus = 80 cm

Hence, perimeter of the rhombus is 80 cm.

Thanks dear. Hope this helps you...

Answer 2

Answer:

perimeter is 4 × side

find side when diagonal given

half of diagonals 16 and 12cm

16^2+12^2 = X^2

256+144 = X^2

400 = X^2

20 = X

PERIMETER = 4×20

= 80 CM