Question

1. The lengths of the sides of atriangleare in the ratio 5:4:3and its perimeter is 96 cm.Find thei) area.the triangleii) Height of the triangle correspondingto thelongest side.​

Answer 1

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Consider the sides of the triangle ABC be 4 x, 5 x and 3x

AB=4x,AC=5x and BC=3x

Perimeter =4x+5x+3x=96

12 x=96

x=

12

96

x=8

Sides are BC=3(8)=24cmAB=4(8)=32cm,

AC=5(8)=40cm

(AC)

2

=(AB)

2

+(BC)

2

[(5x)

2

=(3x)

2

+(4x)

2

]

semi-perimeter of triangle = perimeter/2

=96/2

=48cm.

acc. to heron's formula,area of triangle

48(48−32)(48−40)(48−24)

=[404cm]

2

solution

this is the answer

Answer 2

Answer:

3:4:5 (perimeter 12) = ratio 24:32:40 (perimeter 96)

3=width 4=height hypotenuse = 5

24= width 32 = height. hypotenuse=40

1/2 H*W is area. 24*32*1/2 = 384 sqcm

longest side is 32