Question

1) The lengths of the two diagonals of a
rhombus are 6 cm and 8 cm respectivel
What is the length of its side?
please solve this ​

Answer 1

Answer:

The two diagonals make four equal right triangles, where their hypotenuses are the four sides of the rhombus. The two perpendicular sides are 6:2=3 cm and the other 8:2=4 cm.

From the Pythagorian theorem you ’ve got:

For a rhombus’ side s,

s^2 = 3^2 + 4^2 = 25

and s = √25 = 5 cm

The perimeter is 4*s = 20 cm

Step-by-step explanation:

Please mark me as brainliest and hope this helps you

Answer 2

$let \: abcd \: be \: the \: rhombus \: and \: o \: be \: the \: point \: \\ of \: intersection \: of \: diagonals \: ..which \: bisect \: \\ each \: other \:at \: right \: triangle \\ ab ^{2} = ao ^{2} + bo ^{2} \\ = 3 ^{2} + 4 ^{2} \\ = 9 + 16 \\ = 25 \\ \: hence \: ... \: ab = 5cm$