Question

1. The linear equation 2x - 5y = 7 has _________.

a. an unique solution b. two solutions

c. infinitely many solutions d. no solution

2. The equation x = 7, in two variables can be written as _________.

a. 1×x + 1× y = 7 b. 1×x + 0× y = 7

c. 0×x + 1× y = 7 d. 0×x + 0×y = 7

3. x = 5; y = 2 is a solution of the linear equation _________.

a. 7x +2y = 7 b. 5x +2y = 7

c. x + y = 7 d. 5x + y = 7

4. If a linear equation has solutions (-2, 2), (0, 0) and (2,-2), then it is of the

form ___________.

a. y - x = 0 b. x + y = 0

c. -2x + y = 0 d. -x + 2y = 0

5. The positive solutions of the equation ax + by + c = 0 always lie in the

___________.

a. I quadrant b. II quadrant

c. III quadrant d. IV quadrant​

Answer 1

2. b

5. I quadrant

Step-by-step explanation:

I only know these 2 answers so please forgive me.

Answer 2

1) OPTION C

EXPLAINTION-:$In$$the$$given$$equation$$2x – 5y =>7, for$$every$$value$$of$$x, we$$get$$a$$corresponding$$value$$of$$y$$and$$vice-versa.$ Therefore, the linear equation has infinitely many solutions.

2) OPTION B

EXPLAINTION-:$The$$equation$$x=7, in$$two$$variables$$can$$be$$written$$as.$$Hence,$$the$$required$$equation$$is$$1×x+0×y=7.$

3)OPTION C

EXPLAINTION-:

(a) $x + 2y = 7 x=5,y=2$

puting value of x and y in equation

$5+2(2)=7$

$5+4=7$

$9≠7$ ∵ it is not solution

(b) $5x+2y=7$puting value of x and y on equation

$5(5)+2(2)=7$

$25+4=7$

$29≠7$∵ it is not solution

(c) $x+y=7 (similer)$

$5+2=7$

$7=7$∵ it is solution

(d) $5x+y=7  (similler)$

$5(5)+2=7$

$25+2=7$

$27≠7$ ∵ it is not solution

4)OPTION B

EXPLAINTION-:$If$$a$$linear$$equation$$has$$solutions$$(-2,2)(0,0) and (2,-2), then$$it$$is$$of$$the$$form. Hence, x+y=0$$is$$the$$required$$form$$of$$the$$linear$$equation.$

5) OPTION A

EXPLAINTION-:$The$$positive$$solutions$$of$$the$$equation$$ax+by+c=0$$always$$lies$$in$$the. Solution : We$$know$$that, if$$a$$line$$passes$$through$$the$$Ist$$quadrant,$$then$$all$$solution$$lying$$on$$the$$line$$in$$first$$quadrant$$must$$be$$positive$$because$$the$$coordinate$$of$$all$$points$$in$$the$$Ist$$quadrant$$are$$positive.$

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