Question

1. The lower fixed point (L. F. P.) of a Centigrade thermometer is
+ 10°C, but its upper fixed point (U. F. P.) is 100°C. What will be
the reading of this thermometer if it is dipped in a liquid whose actual
temperature is 40°C.​

Answer 1

Answer:

Here is your answer

Explanation:

Let θ

0

be the lower fixed point of the faulty thermometer and 'n' be the number of divisions between its lower and the upper fixed points. If a temperature C on celsius scale corresponds to temperature θ on the scale of faulty thermometer, then

100

C

=

n

θ−θ

0

Here, θ

0

=10

o

,n=90−10=80 and θ=61

o

Therefore, the equation becomes

100

C

=

90−10

61−10

C=

80

56

×100

C=63.75

o

C