Question

1 The lower part of a circus tent is a right circular cylinder and its upper
part is right circular cone. The diameter of the base of the tent is
56 m and height of the cylindrical part is 15 m. The total height of the
tent is 60 m. How many square metres of canvas is required for the
tent ? Find the volume of the air space in tent. ​

Answer 1

Answer:

Solution :-

Radius of the base = Diameter/2

⇒ 56/2 = 28 m

Height of the cylindrical part = 15 m

Curved Surface Area of Cylinder = 2πrh

⇒ 2*22/7*28*15

= 2640 m²

Curved Surface Area of Cone = πrl

To find the Curved Surface Area of Cone, first we have to calculate the slant height of cone.

Slant Height of Cone = l = √r² + h²

⇒ √28² + 45²

⇒ √784 + 2025

⇒ √2809

⇒ Slant height of cone = 53 m

Curved Surface Area of Cone = πrl

⇒ 22/7*28*53

= 4664 m²

Total area of the cylindrical part and the conical part = 2640 + 4664 

= 7304 m²

So, the area of the canvas required is 7304 m²

Step-by-step explanation:

TAG ME AS BRAINLIEST ✨