Question

1 The maximum height reached by a projectile is 38m.
At the horizantal
Velocity at the inside is 32m, Find thita
initial Velocity? ​

Answer 1

intial velocity will be 45meter per second

Answer 2

Explanation:

Given The maximum height reached by a projectile is 38 m. At the horizontal Velocity at the inside is 32 m, Find the initial Velocity?  

• Given maximum height reached by the projectile
•                               h = 38 m
•   So h = u^2 sin^2 x / 2g
•       Taking g = 10 m/s
•      38 = u^2 (1 – cos^2 x) / 2 x 10
•       38 = u^2 – u^2 cos^2 x / 20
•       38 = u^2 – (32)^2 / 20 (since horizontal velocity u cos x = 32 m / s
•       38 = u^2 – 1024 / 20
•        760 =  u^2 – 1024
•            u^2 = 1784
•            u = 42.23 m/s
• Therefore the initial velocity is 42.23 m/s

Reference link will be

https://brainly.in/question/15564786