Question

1.
The mean and median of a distribution are 14 and 15
value of mode is
(A) 16
(В) 17
C) 18
D 13​

Answer 1

Given ,

Mean = 14

Median = 15

We know that , the relationship between mean , median and mode is given by

$\boxed{ \tt{3(Median )= 2(Mean)+ Mode }}$

Thus ,

3(15) = 2(14) + Mode

45 = 28 + Mode

Mode = 45 - 28

Mode = 17

Therefore , the correct option is (B) i.e 17

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Answer 2

Answer:

$\huge{ \bold{ \mathfrak{ \boxed{ \star{ \mathtt{ \orange{answer}{} }{} }{} }{} }{} }{} }{}$

Answer :-

Given that:-

Mean = 14

Median = 15

Mode = x

Step-by-step explanation:

Solution :-

• We know the relationship between Mean, median and Mode

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$\bold{ \red {3 \: (median) = 2 \: mean + mode}{} {}{} }{}$

Thus we can Conclude that,

• 3(15) = 2(14)+mode

• 45 = 28+ mode

• Mode = 45-28

$\sf{ \green{mode \: = 17 \: option \: b \: }{} }{}$

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