Question

1) The mean of the following distribution is 50.
X
F
10
17
30
5a + 3
50
32
70
7a – 11
90
19
Find the value of a and hence the frequency of the observation 30 and 7
mes the results were as follows:​

Answer 1

Answer:

Mean =

∑x

i

∑x

i

f

i

⇒

10+30+50+70+90

10(17)+30(5a+3)+50(32)+70(7a−11)+90(19)

=50

⇒

250

2800+640a

=50

⇒2800+640a=12500

640a=9700

a=15.15625.

Step-by-step explanation:

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Answer 2

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