Question

1. The number of units of a certain item sold by a company in 2010 was 20% higher than thenumber of units it sold in 2009. If the number of units of the item sold in 2009 was 3,000less than that in 2010, how many units did the company sell in 2009?A. 12,000B. 15,000C. 16,000D. 18,000E 24,000​

Answer 1

$\rm\purple{\underbrace{Answer-OPTION-(D)}}$

$\sf\large\underline{Given:}$

$\tt{\implies Items\: sold\:in\:2010=20\%\:higher\:than\:in\:2009}$

$\tt{\implies Items\:sold\:in\:2009\:less\:3000\:than\:2010}$

$\sf\large\underline{To\: Find:}$

$\tt{\implies Items\:sold\:in\:2010=?}$

$\sf\large\underline{Solution:}$

$\tt{\implies The\: items\:be\:x\:sold\:in\:2009}$

$\sf\small\underline{Given\:that:}$

• The number of units of a certain item sold by a company in 2010 was 20% higher than the number of units it sold in 2009. If the number of units of the item sold in 2009 was 3,000less than that in 2010]

$\rm{\implies x\times\:120\%-x=3000}$

$\tt{\implies \dfrac{120x}{100}-x=3000}$

$\tt{\implies \dfrac{120x-100x}{100}=3000}$

$\tt{\implies \dfrac{20x}{100}=3000}$

$\tt{\implies \dfrac{x}{5}=3000}$

$\tt{\implies x=3000\times\:5}$

$\tt{\implies x=15000}$

• Now calculate the item sold in 2010]

$\tt{\implies Items\: sold\:_{(in\:2010)}=No\:of\: items\:in\:2009+3000}$

$\tt{\implies Items\: sold\:_{(in\:2010)}=15000+3000}$

$\tt{\implies Items\: sold\:_{(in\:2010)}=18000}$

$\bf\large{Hence,}$

$\tt\orange{\implies Items\: sold\:_{(in\:2010)}=18000}$