1. The number of zeroes of the given polynomial. (x+1)+(x+2)(x-3) is options in the following questions. (a)2 (b)3 (c)4 (d)1
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Answer:
c. 4 zeroes
Step-by-step explanation:
Polynomial:
(x + 1)^2 (x + 2) (x - 3)
Zeroes:
(x + 1)^2 = 0
(x + 1)(x + 1) = 0
x + 1= 0, x + 1 = 0
x = - 1 , - 1
(x + 2) = 0
x = - 2
(x - 3) = 0
x = 3
Hence zeroes are - 1 , -1 , - 2 , 3
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