Question

1. The ones digit in a 2-digit number is 3 times the digit at the tens place. If the sum of the two digits is 8, find the number.​

Answer 1

Answer:

Let the digit at tens place be x. Now, digit at ones place = 3x ( given in question).

Now,

3x+x=8

4x=8

x=8/4

x=2

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Answer 2

Step-by-step explanation:

let the digit at tens place be x

then digit at ones place =3x

Number formed = x×10+3x=13x

Also x+3x=8

x=2

So Number is = 13×2=26

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