Question

1. The output of a step-down transformer is measured to be 12V when connected to a 24 W light bulb. Calculate the value of peak current flowing through it.
2. A battery of emf 18V and an internal resistance of 3 is connected to another battery of emf 6V and an internal resistance of 2.5 in such a way that they are opposing each other. If the circuit is closed then find,
a) Current flowing in the circuit,
b) Electric Power in the 2 batteries,
c) Electric Power consumed in the 2 batteries.
3. There are 24 graduations (0 to 24) on the dial of a galvanometer and on passing 12A current it shows a deflection of 1 division. If its resistance is 18, then how do you convert it into an Ammeter measures 1A and a Voltmeter which measures a pot. Difference of 1V?

Answer 1

Dear Student.

Question 1.1. The output of a step-down transformer is measured to be 12V when connected to a 24 W light bulb. Calculate the value of peak current flowing through it.

Answer:

Output of a step-down transformer is measured to be 12V.

Power of light bulb = 12W

Power(P)= vi

Where v is voltage and i is current

hence,   i= P/v

               = 12/24

               =1/2

               =0.5 A

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