1. The perimeter of a rectangle is 13 cm and width is 11/4 cm, find its length.
2. Find the square root of 12.25.
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2
1.) perimeter of rectangle = 13 cm
width = 11/4 cm
length = ?
A.T.Q.
perimeter = 2(L+B)
13 = 2(L+11/4)
13 = 2L + 11/2
13-11/2 = 2L
26-11/2 = 2L
15/2 = 2L
L = 15/2x2
L = 15/4
2.) 12.25
= √12.25
= 3.5
Answered by
1
Answer:
(1) perimeter=13cm
width = 11/4cm
length = ?
Now, we know that the perimeter of rectangle is = p=2(l+b)
so, 13=2(l+11/4)
13 = 2l+11/2
13-11/2 =2l
15/2=2l
l=15/4
(2) square root of 12.25
✓12.25
=3.5ans
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