Question

1. The perimeter of a rectangle is 178 cm. The length of the rectangle is 39 cm more than the bread
the rectangle. Find the side of the square whose area is same as that of rectangle.​

Answer 1

Answer:

Perimeter of rectangle =40 cm (given)

Perimeter of rectangle =40 cm (given)condition :- length = 2× breadth +2

Perimeter of rectangle =40 cm (given)condition :- length = 2× breadth +2⇒l=2b+2

Perimeter of rectangle =40 cm (given)condition :- length = 2× breadth +2⇒l=2b+2perimeter p=2(l+b)=40

Perimeter of rectangle =40 cm (given)condition :- length = 2× breadth +2⇒l=2b+2perimeter p=2(l+b)=40⇒2(2b+2+b)=40

Perimeter of rectangle =40 cm (given)condition :- length = 2× breadth +2⇒l=2b+2perimeter p=2(l+b)=40⇒2(2b+2+b)=40⇒2(3b+2)=40

Perimeter of rectangle =40 cm (given)condition :- length = 2× breadth +2⇒l=2b+2perimeter p=2(l+b)=40⇒2(2b+2+b)=40⇒2(3b+2)=40⇒6b=40−4=36

Perimeter of rectangle =40 cm (given)condition :- length = 2× breadth +2⇒l=2b+2perimeter p=2(l+b)=40⇒2(2b+2+b)=40⇒2(3b+2)=40⇒6b=40−4=36∴b=6cm

l=2×6+2=12+2=14cm

l=2×6+2=12+2=14cm∴ length =14 cm, breadth =6 cm

Step-by-step explanation:

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Answer 2

Answer:

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Step-by-step explanation: