Question

(1) The perimeter of a rectangle is 80 metres and its length is
one metre more than twice the breadth. What are its length and
breadth?
Buddies I need the answer with the full step . Please....​

Answer 1

Given :

• Perimeter of Rectangle is 80m.
• Length of rectangle is one more than twice its breadth.

To Find :

• Length and Breadth of Rectangle.

Solution :

$\longmapsto\tt{Let\:Breadth\:be=x}$

As Given that length of rectangle is one metre more than twice its breadth.So ,

$\longmapsto\tt{Length=2x+1}$

Using Formula :

$\longmapsto\tt\boxed{Perimeter\:of\:Rectangle=2(l+b)}$

Putting Values :

$\longmapsto\tt{80=2(2x+1+x)}$

$\longmapsto\tt{\cancel\dfrac{80}{2}=3x+1}$

$\longmapsto\tt{40-1=3x}$

$\longmapsto\tt{39=3x}$

$\longmapsto\tt{x=\cancel\dfrac{39}{3}}$

$\longmapsto\tt\bold{x=13}$

Value of x is 13..

Therefore :

$\longmapsto\tt{Length\:of\:Rectangle=2(13)+1}$

$\longmapsto\tt{26+1}$

$\longmapsto\tt\bold{27m}$

$\longmapsto\tt{Breadth\:of\:Rectangle=x}$

$\longmapsto\tt\bold{13m}$