1. The perimeter of a rectangular lot is given as P = 2L + 2W. Suppose the perimeter (
P) is 45m, the value length (L) is 3/s, and the value width (W) is s/5, what is the value of s?
Answers
Answered by
2
Step-by-step explanation:
nndhrjbsklskrhjdnrbid
Answered by
3
Given : . The perimeter of a rectangular lot is given as P = 2L + 2W.
perimeter (P) is 45m
value length (L) is 3/s, and the value width (W) is s/5,
To Find : Value of s
Solution:
P = 2L + 2W
L = 3/s
W = 5/s
P = 45
=> 45 = 2(2/s) + 2(5/s)
=> 45 = 4/s + 10/s
=> 45 = 14/s
=> s = 14/45
value of s = 14/45
Learn More
What is the area of the jogging track which is 2 m wide that runs ...
brainly.in/question/11147790
The sides of a rectangular park are in the ratio 4:3. if its area is 2028 ...
brainly.in/question/8164255
Similar questions