Math, asked by mohdowaisw, 1 month ago

1. The perimeter of a rectangular swimming pool is 154m. Its length is 2m more than twice its
breadth. What are the length and breadth of the pool?
OR
125%
Find 'x' in the following fig
125​

Answers

Answered by Vikhyath1011
1

Answer:

Step-by-step explanation:

PERIMETER - 154m

Let breadth be (x)m

Then length will be - (2x + 2)m

Perimeter of rectangle - 2(l+b)

SUBSTITUTING THE ABOVE VALUES:

2( 2x+2+x) = 154

2 ( 3x+2) =  154

6x + 4 = 154

6x = 150

x = 25

Therefore , the breadth , x , is 25m and the length, 2x +2 , is 52m

HOPE THIS HELPS :)

Answered by Anonymous
5

Given that , The perimeter of a rectangular swimming pool is 154m and it's length is 2m more than twice it's breadth.

Need To Find , Length and Breadth of Rectangular swimming pool ?

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

❍ Let's Consider that Breadth of Rectangular swimming pool be x m .

⠀⠀⠀⠀⠀Given that ,

⠀➠⠀The Length is 2m more than twice it's breadth.

Therefore,

  • Length of Rectangular Swimming pool is ( 2x + 2 ) m .

As , We know that ,

\qquad \star \:\:\:\underline{\boxed{{\frak{\pink{ \:\: Perimeter _{(\:Rectangle \:)} \:\:=\: 2 \:\bigg( \: Length  \: +\:Breadth \:\bigg) \:sq.units \:\:}}}}}\\\\

⠀⠀Where,

  • Length of Rectangular swimming pool is ( 2x + 2 ) m ,
  • Breadth of Rectangular swimming pool is x m , &
  • Perimeter of Rectangular swimming pool is 154 m .

\qquad \dashrightarrow \sf \:\: Perimeter _{(\:Rectangle \:)} \:\:=\: 2 \:\bigg( \: Length  \: +\:Breadth \:\bigg) \: \\\\

⠀⠀⠀⠀⠀⠀\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}\\

\qquad \dashrightarrow \sf \:\: Perimeter _{(\:Rectangle \:)} \:\:=\: 2 \:\bigg( \: Length  \: +\:Breadth \:\bigg) \: \\\\

\qquad \dashrightarrow \sf \:\: 154 \:\:=\: 2 \:\bigg( \: x  \: +\:( 2x + 2 ) \:\bigg) \: \\\\

\qquad \dashrightarrow \sf \:\: \dfrac{154}{2} \:\:=\: \:\bigg( \: x  \: +\:( 2x + 2 ) \:\bigg) \: \\\\

\qquad \dashrightarrow \sf \:\: \cancel{\dfrac{154}{2}} \:\:=\: \:\bigg( \: x  \: +\:( 2x + 2 ) \:\bigg) \: \\\\

\qquad \dashrightarrow \sf \:\: 77 \:\:=\: \:\bigg( \: x  \: +\:( 2x + 2 ) \:\bigg) \: \\\\

\qquad \dashrightarrow \sf \:\: 77 \:\:=\: \: \: x  \: +\: 2x + 2  \: \: \\\\

\qquad \dashrightarrow \sf \:\: 77 \:\:=\: \: \: 3x + 2  \: \: \\\\

\qquad \dashrightarrow \sf \:\: 77 - 2 \:\:=\: \: \: 3x \:\: \\\\

\qquad \dashrightarrow \sf \:\: 75 \:\:=\: \: \: 3x \: \: \\\\

\qquad \dashrightarrow \sf \:\: \cancel {\dfrac{75}{3}} \:\:=\: \: \: x \: \: \\\\

\qquad \dashrightarrow \sf \:\: 25 \:\:=\: \: \: x \: \: \\\\

\qquad \dashrightarrow \sf \:\: x \:\:=\: \: \: 25\: \: \\\\

\qquad \dashrightarrow \underline {\boxed {\pmb{\frak{\purple { \:\: x \:=\:25 \:m \:}}}}}\:\:\bigstar \\\\

Therefore,

  • Length of Rectangular swimming pool is ( 2x + 2 ) = 2(25)+ 2 = 52 m
  • Breadth of Rectangular swimming pool is x = 25 m

 \therefore \:\:\underline {\sf Hence, \: The \:Length \:and \:Breadth \:Rectangular \:swimming \:pool \:are \: \bf 52 \:m \:and \: 25 \: m \:\sf , respectively \:}\\\\

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