Question

1. The perimeter of a triangle is 40 cm and its hypotenuse is 17cm.calculate its area and verify the result by using.Heron's formula


2.If the right triangle , the side containg the right angles, one side exists the other by 4cm.if the of area of triangle is 96 cm ² .find the perimeter of the triangle.

there are two questions please answer this questions by full explanation. ​

Answer 1

Answer:

idk

Step-by-step explanation:

Answer 2

Answer:

Ques 1.

perimeter of triangle= sum of all sides

40=17+a+b

a+b=40-17

a+b=23

a=23-b

by Pythagoras theorem

h^2=p^2+b^2

17^2=a^2+b^2

289=(23-b)^2+b^2

289=529-46b+b^2+b^2

529-289-46b+2b^2=0

240-46b+b^2=0

240-40b-6b+b^2=0

40(6-b)-b(6-b)=0

(40-b)(6-b)

Ques 2.

let one side be x and another X+4

Area =1/2×base×height

96=1/2×x×(x+4)

192=x^2+4x

x^2+4x-192=0

x^2+16x-12x-192=0

X(X+16)-12(X+16)=0

(X+16)(x-12)=0

so

X=-16or12

side of a triangle can not be negative

so one side X =4

and another side X+4=16

by Pythagoras theorem

h^2=p^2+b^2

= 12^2+16^2

=144+256

=400

therefore hypotenuse is 20cm

now

perimeter of triangle= sum of all sides

=12+16+20

=48cm