1)The Perimeter of an isosceles triangle is 30cm.The length of its congruent sides is 3cm more than its base.Find the lengths of all sides.
2)Sum of two numbers is 97.If the greater number is divided by the smaller number,the quotient is 7 and the remainder is 1.Find the numbers
Plz solve both que. now....its vvv urgent
Answers
Answered by
10
so let tje base be x
now the congruent sides will be x+3
perimeter is given =30
so
(x+3)+(x+3)+x=30
x+3+x+3+x=30
it becomes
3x+6=30
3x=30-6
3x=24
x=24/3
x=8
now the congruent sides will be x+3
perimeter is given =30
so
(x+3)+(x+3)+x=30
x+3+x+3+x=30
it becomes
3x+6=30
3x=30-6
3x=24
x=24/3
x=8
Linakshi:
Thnx...and why is the solution of 2nd one
Answered by
3
Answer: X=85,Y=12
Step-by-step explanation:
Let greater number be X and smaller number be y
According to first condition,
X + y =97.......(i)
We know that,
Dividend=
divisor×quotient+remainder
Therefore,
X=y×7+1
X=7y+1 .....(ii)
Putting value of equation 2 in equation 1
X+y=97
7y+1+y=97
8y+1=97
8y=97-1
8y=96
Y=96/8
Y=12.
Therefore,
X+y=97
X=97-12
X=85.
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