Question

1. The perimeter of the quadrilateral ABCD formed by A(-3, 1), B(0,5), C(4,8), D(1.4) taken in
that order is
A(-3, 1), B[0, 5), C (4, 8), D[1, 4) లు వరున శీర్షాలతో ఏర్పడు చతుర్భుజము ABCD యొక్క చుట్టుకొలత

(1)16√2
(2) 25
(3) 20
(4) 10.
answer me fast
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Answer 1

hope it is useful for you

Answer 2

Answer:

Perimeter of the quadrilateral ABCD is 20 units

option (3) is correct

Step-by-step explanation:

Formula used:

The distance between two points $(x_1,y_1)\:and\:(x_2,y_2)\:is\:\:\:d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

Given:

A(-3, 1), B(0, 5), C (4, 8), D(1, 4)

First we find lengths of all sides of the quadrilateral.

$AB=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

$AB=\sqrt{(-3-0)^2+(1-5)^2}$

$AB=\sqrt{(-3)^2+(-4)^2}$

$AB=\sqrt{9+16}$

$AB=\sqrt{25}$

$AB=5$

$BC=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

$BC=\sqrt{(0-4)^2+(5-8)^2}$

$BC=\sqrt{(-4)^2+(-3)^2}$

$BC=\sqrt{16+9}$

$BC=\sqrt{25}$

$BC=5$

$CD=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

$CD=\sqrt{(4-1)^2+(8-4)^2}$

$CD=\sqrt{(3)^2+(4)^2}$

$CD=\sqrt{9+16}$

$CD=\sqrt{25}$

$CD=5$

$AD=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

$AD=\sqrt{(-3-1)^2+(1-4)^2}$

$AD=\sqrt{(-4)^2+(-3)^2}$

$AD=\sqrt{16+9}$

$AD=\sqrt{25}$

$AD=5$

Perimeter of the quadrilateral ABCD

$=AB+BC+CD+AD$

$=5+5+5+5$

$=20\:units$