Question

1.The perpendicular distance between the point of application of force and the fulcrum is1.5 m, when a force of 70 N acts on a rigid body. Calculate the moment of force *
135 Nm
105 Nm
105 N
46.66 Nm​

Answer 1

Explanation:

Force (F) = 70 N

Force (F) = 70 NPerpendicular distance = 1.5m

Force (F) = 70 NPerpendicular distance = 1.5m ∴ Moment of Force = F x perpendicular distance

Force (F) = 70 NPerpendicular distance = 1.5m ∴ Moment of Force = F x perpendicular distance= 70 x 1.5 = 105 Nm.

Answer B is correct

Answer 2

Concept:

Force can also be defined intuitively as a push or a pull. Force is a vector quantity as it has both magnitude and direction.

Given:

The perpendicular distance between the point of application and the turning point is $1.5m$.

The force on a rigid body is $70N$.

Find:

The moment of force.

Solution:

We have,

Force $=70N$ and perpendicular distance $=1.5m$ .

The moment of force is equal to the force acting on the body times the perpendicular distance.

The moment of force is:

$=70N\times 1.5m\\=105Nm$

The moment of force is $105Nm$.

#SPJ3