Question

1.
The pH of 0.01 M NaOH (aq) solution will be
[NEET-2019 (Odisha)]
(1) 9
(2) 7,01
(3) 2
(4) 12​

Answer 1

Here u go ♥️♥️♥️

Option 4) 12 is your answer.

Hope It helps u.......✌️✌️✌️⬅️⬅️

Answer 2

Answer:

Explanation:Moles of NaOH = 0.01=10^-2

P(OH) = -log(H+)

=-log(10^-2)

=-2(log 10)

=-2. (Log 10=1)

pH=14 - P(OH)

=14-2

=12