Question

1. The potential difference between the terminals of an electric heater is 110 V, when it draws a
current of 5A from the source . What current will the heater draw and what will be its wattage if
the potential difference is increased to 220 V ? Consider that the resistance of the heater
element does not change with temperature.​

Answer 1

V = 110V

I = 5A

R = V/I = 110/5 = 22 ohm

V' = 220V

R = 22 ohm

I = V/R

= 220/22 = 10A

P = I²R

= (10)² × 22 = 2200W = 2.2kW

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Answer 2

Answer:

The current is $10A$

Power is $2.2kW$

Explanation:

It is given that potential difference between terminals of electric heater is $110V$

Current drawn from source is $5A$

Potential difference is increased to $220V$.

Also, the resistance of the heater element does not change with temperature.​

We know that resistance is ratio of voltage and current.

$R=\frac{V}{I}$

Hence, $R=22ohm$

$V^{'} =220V$

Hence, current drawn is $I=\frac{V}{R} =\frac{220}{22} =10A$

Power is $P=I^{2} R$

$P=10*10*22=2.2kWh$

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