Question

1. The power of a motor is 200W. If the unit of
length is halved, that of mass is doubled and
that of time is also doubled, then the power of
the motor in the new system is​

Answer 1

power = time/workdone=M¹L²T-³

Power =200=M¹L²T-³......(1)

Let new power rating =M*L*²T*-³

M=2M*, L=L*/2 and T=2T*......(2)

Putting (2) in (1),

200=2M*L*²/4×T-³/8

M*L*²T-³=3200 new units

Hope it helps you...!

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Answer 2

Explanation:

the numbers are 6 and 4

there sum is 6+4 = 10

there difference 6-4 = 2

up answer is correct please mark that brainliest

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