1. The present age of father is five times the age of the so
Five years ago, the age of father was ten times the age
his son at that time. How old is father at present?
445 years 2) 40 years
3) 48 years
4) 49 years
5) none of these
2. Meeta is four years older than Sunitha. After eight years
the sum of their ages will be three times that of their
present ages. What is the age of Meeta?
1)10 yrs. 2) 8 yrs *3) 6 yrs.
4) Data inadequate 5) none of these
3. Father's age is 25 years more than the son's age. Four
years hence, father's age will become 1 year less than thrice
the son's age. What is father's present age?
1) 31 years
2) 38 years
3) 34 years
4) 36 years
5) none of these
Answers
Answer:
1 ans)Let F and S be the current ages of the father and son respectively.
From the first statement: F = 5 S
From the second statement:
F - 5 = 10(S - 5).
So F - 5 = 10S - 50 or F = 10S - 45
Combining this last equation with the first:
5S = 10S - 45
=>> 45 = 5S (adding 45 to both sides and subtracting 5S from both sides)
Dividing by 5 gives us 9 = S
So the father is 45 and the son is 9.
Five years ago they were 40 and 4.
2 ans)Let Sunitha be x years old
Meeta is x + 4
8 years later
Sunitha = x + 8
Meeta = x + 4 + 8 = x + 12
Solve x:
Their sum will be 3 times their present age
(x + 8) + (x + 12) = 3 [ ( x + (x + 4) ]
x + 8 + x + 12 = 3 (x + x + 4)
2x + 20 = 3(2x + 4)
2x + 20 = 6x + 12
4x = 8
x = 2
Find Meeta's age:
Meeta = x + 4 = 2 + 4 = 6
Answer: Meeta is 6 years old
3ans)Son's age =x
Father's age = x + 25
after 4 years son's age = x + 4
after 4 years Father's age = x + 29 or 3(x+4) - 1
x + 29 = 3x + 12 - 1
2x = 29 -11
x = 18/2 = 9
Father's present age = 9 + 25 = 34years
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Answer:
according to question
X=5y
after 5 year ago
(x-5)=10(y-5)
substitute equition first and second
5y-10y=-45
-5y=-45
putting y=9 and we get
x=5×9
hence present age of his father is 45year