Question

1. The present ages of A and B are in the ratio 7:5. Ten years later, their ages will
be in the ratio 9:7. Find their present ages.​

Answer 1

Step-by-step explanation:

Let the present age of A= 7x years

The present age of B= 5x years

After 10 years, their ages will be

A=7x+10 years and

B=5x+10 years

The ratio of their ages after 10 years is 9:7.

∴

$\frac{7x + 10}{5x + 10} = \frac{9}{7}$

⇒49x+70=45x+90

⇒49x−45x=90−70

⇒4x=20

⇒x=5

∴ Present age of A= 7×5=35 years and present

age of B= 5×5=25 years.

Answer 2

Step-by-step explanation:

this is the answer

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