Math, asked by maheshbarfa8090, 3 months ago

1. The present population of a town is 5,50,000.
There is an annual increase of 4% in the
population. What will be the population after 3
years​

Answers

Answered by 5812ishita
5

\huge\mathfrak{Answer}

Let's do it step-by-step:

1- Present population of a town =5,50,000

Rate of Increase = 4%

Time=3yrs

2- Now,

A = P{1+R/100}⁴

A=5,50,000{1+4/100}⁴

A= 5,50,000{1+1/25}⁴

A = 5,50,000{(25+1)/25}⁴

A = 5,50,000{26/25}⁴

A = 5,50,000×[26/25×26/25×26/25×26/25]

A = 5,50,000×456,976/390,625

A=5,50,000×1.16

A=638000

° THE POPULATION WILL BE 638000 AFTER 3 YRS

Answered by BrainlyTopper97
104

{\huge{\boxed{\mathrm{\underline{\blue{A}{\green{n}{\red{s}{\orange{w}{\pink{e}{\purple{r}{\orange{:}}}}}}}}}}}}

The population of town after three years will be 6,18,675.2.

Step-by-step explanation:

Given :-

  • Present population of the town = 5,50,000
  • Increase percentage of population in the town = 4% annually

To Find :-

  • Population of the town after 3 years.

Solution :-

Population of the town after 1 year = Initial Population (Initial Population × Increase %)

\Longrightarrow {\mathsf{5,50,000 + (5,50,000 \ of \ 4\%)}}\\\\\Longrightarrow {\mathsf{5,50,000 + (5,50,000 \times \dfrac{4}{100})}}\\\\\Longrightarrow {\mathsf{5,50,000 + (5,500 \times 4)}}\\\\\Longrightarrow {\mathsf{5,50,000 + 22,000}}\\\\\Longrightarrow {\mathsf{5,72,000}}\\\\\\{\boxed{\underline{\large{\mathsf{{\green{Population} \ {\red{of} \ {\orange{the} \ {\purple{town} \ {\pink{after} \ {\blue{one} \ {\green{year =} {\orange{5,72,000}}}}}}}}}}}}}}

Population of the town after 2 years = Population after 1 year (Population after 1 year × Increase %)

\Longrightarrow {\mathsf{5,72,000 + (5,72,000 \ of \ 4\%)}}\\\\\Longrightarrow {\mathsf{5,72,000 + (5,72,000 \times \dfrac{4}{100})}}\\\\\Longrightarrow {\mathsf{5,72,000 + (5,720 \times 4)}}\\\\\Longrightarrow {\mathsf{5,72,000 + 22,880}}\\\\\Longrightarrow {\mathsf{5,94,880}}\\\\\\{\boxed{\underline{\large{\mathsf{{\green{Population} \ {\red{of} \ {\orange{the} \ {\purple{town} \ {\pink{after} \ {\blue{two} \ {\green{years =} {\orange{5,94,880}}}}}}}}}}}}}}

Population of the town after 3 years = Population after 2 years (Population after 2 years × Increase %)

\Longrightarrow {\mathsf{5,94,880 + (5,94,880 \ of \ 4\%)}}\\\\\Longrightarrow {\mathsf{5,94,880 + (5,94,880 \times \dfrac{4}{100})}}\\\\\Longrightarrow {\mathsf{5,94,880 + (5,948.8 \times 4)}}\\\\\Longrightarrow {\mathsf{5,94,880 +23,795.2}}\\\\\Longrightarrow {\mathsf{6,18,675.2}}\\\\\\{\boxed{\underline{\large{\mathsf{{\green{Population} \ {\red{of} \ {\orange{the} \ {\purple{town} \ {\pink{after} \ {\blue{three} \ {\green{years =} {\orange{6,18,675.2}}}}}}}}}}}}}}

Hence,

  • The population of the town after 3 years will be 6,18,675.2.

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