Physics, asked by AathmajaA, 4 months ago

1
The pressure of water in a pipe on the ground floor is 60,000 Pa and on the first floor is 20,000 Pa. If the density of water is 1000Kgmand g=
10ms-2, the height of the first floor is

Answers

Answered by shruti4356
0

Explanation:

pressure on ground floor = pressure on the first floor + hdg

60,000 = 20,000 + hdg

60,000 = 20,000 + h × 10^3×10

h × 10^4 = 60,000 - 20,000

h = 40,000 / 10,000

h = 4

I hope it helps you

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