Question

1. The probability that the sum of the values of 2 dice when thrown is equal to 8 is:

 1/36

 2/36

 3/36

 5/36



2. Cards are drawn sequentially without replacement from a pack. The probability that an ace is drawn on the third draw from a well shuffled pack of cards 
   given that the first and second ones were also aces is:

 2/50

 3/51

 4/52

 12/(51*52)



3. A family has three children. Given that one of the children is a girl, what is the probability that all children are girls?

 1/2

 1/4

 1/8

 1/7


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Answer 1

Answer:

1. 2|36

2. 3|51

3. 1|8follow mee plzzz

Answer 2

Answer:

5/36 , 12/(51*52) and 1/8.

Step-by-step explanation:

For the first case the sum of two values of a dice of being 8 can be of 5 types and since 2 dice are thrown hence, total outcome is 36. So, the probability will be 5/36.

For the second case since the cards are not replaced hence for the first pickup of ace the probability is 4/52. As the total outcome is 52 and the number of ace cards are 4. So, probability of getting an ace again without replacement will be 3/51. So, the result is 4/52*3/51.

Since, the family has 3 children and among them one is girl. So, the other two can be boy or girl or both boys. So, the probability will be 1/2*1/2*1/2 = 1/8.