Question

1. the product of tanay's age (in years)five years ago and his age(in years) ten years later is 16. Determine tanay's present age....

Answer 1

Let tanay's present age be x yrs

five yrs ago tanay's age = x-5

ten yrs later tanay's age =x+10

according to the question.,

=(x-5)(x+10)=16

=x^2 +10x-5x-50=16

=x^2+5x-66=0

=x^2+11x-6x-66=0

=x (x+11)-6 (x+11)=0

=(x-6)(x+11)=0

=x=6 or x=-11

since age is positive tanay's present age =6yrs

Hope it helps

Answer 2

Answer:

hlo..

Step-by-step explanation:

Let the present age of Tanay be x years.

Then, from the given information, we have:

(x - 5) (x + 10) = 16

x2 + 5x - 50 = 16

x2 + 5x - 66 = 0

x2 - 6x +11x - 66 = 0

x(x - 6) +11(x - 6) =0

(x - 6)(x +11) = 0

x = -11 or 6

Rejecting x = -11, as age cannot be negative.

Present age of Tanay is 6 years