Question

1. The product of two numbers is 2,352. If one of the number is 24, find the other?

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Answer 1

Step-by-step explanation:

LCM=84s,HCF=s

LCM=84s,HCF=sLCM+HCF=2550

LCM=84s,HCF=sLCM+HCF=255084s+s=2550

LCM=84s,HCF=sLCM+HCF=255084s+s=255085s=2550

LCM=84s,HCF=sLCM+HCF=255084s+s=255085s=2550s=

LCM=84s,HCF=sLCM+HCF=255084s+s=255085s=2550s= 85

LCM=84s,HCF=sLCM+HCF=255084s+s=255085s=2550s= 852550

LCM=84s,HCF=sLCM+HCF=255084s+s=255085s=2550s= 852550

LCM=84s,HCF=sLCM+HCF=255084s+s=255085s=2550s= 852550 =30

LCM=84s,HCF=sLCM+HCF=255084s+s=255085s=2550s= 852550 =30LCM×HCF= Product of numbers

LCM=84s,HCF=sLCM+HCF=255084s+s=255085s=2550s= 852550 =30LCM×HCF= Product of numbers84s×s=360×p

LCM=84s,HCF=sLCM+HCF=255084s+s=255085s=2550s= 852550 =30LCM×HCF= Product of numbers84s×s=360×p84×30×30=360×p

LCM=84s,HCF=sLCM+HCF=255084s+s=255085s=2550s= 852550 =30LCM×HCF= Product of numbers84s×s=360×p84×30×30=360×pp=

LCM=84s,HCF=sLCM+HCF=255084s+s=255085s=2550s= 852550 =30LCM×HCF= Product of numbers84s×s=360×p84×30×30=360×pp= 360

LCM=84s,HCF=sLCM+HCF=255084s+s=255085s=2550s= 852550 =30LCM×HCF= Product of numbers84s×s=360×p84×30×30=360×pp= 36075600

LCM=84s,HCF=sLCM+HCF=255084s+s=255085s=2550s= 852550 =30LCM×HCF= Product of numbers84s×s=360×p84×30×30=360×pp= 36075600

LCM=84s,HCF=sLCM+HCF=255084s+s=255085s=2550s= 852550 =30LCM×HCF= Product of numbers84s×s=360×p84×30×30=360×pp= 36075600 =210,

LCM=84s,HCF=sLCM+HCF=255084s+s=255085s=2550s= 852550 =30LCM×HCF= Product of numbers84s×s=360×p84×30×30=360×pp= 36075600 =210, Therefore, , A is the correct answer.

Answer 2

Answer:

Answer will be 98

Step-by-step explanation:

First , make an equation keeping the second number as x.

Therefore , the equation will be 24 × x = 2352

Then transpose 24 to RHS

x= 2352÷24

x = 98