Question

1.The quadratic polynomial whose sum and product of zeroes are -8 and 12 respectively is​

Answer 1

Answer :

Sum of zeroes = -8

Product of zeroes = 12

Equation formed is,

x²-Sum(x)+Product = 0

x² -(-8)x + 12 = 0

x² + 8x +12 = 0

Answer 2

QUESTION:

1.The quadratic polynomial whose sum and product of zeroes are -8 and 12 respectively is

ANSWER:

We know that; quadratic polynomial is in the form of

$\huge\red {a {x}^{2} + bx + c = 0}$

where;

b = sum of zeroes

c = product of zeroes

in other form we can write the equation;

$\green {{x}^{2} - (sum \: of \: zeroes)x + product \: of \: zeroes}$

$\red {(remember \: before \: the \: sum \: of \: zeroes \: there \: is \: negative \: sign \: always)}$

now come to main question;

GIVEN:

Sum of zeroes = -8

product of zeroes = 12.

Using the formula; and putting the value;

${x}^{2} - ( - 8)x + 12 \\ {x}^{2} + 8x + 12$

FINAL ANSWER:

$\huge\red { {x}^{2} + 8x + 12}$

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