Question

1. The quotient is 68. The divisor is 9.Give the dividend
2.how many 4's are there in 130
3.what will be the remainder if 261 is divided by 5?
4.in 625 divide 10, what is the remainder?
5.the quotient is 30, the dividend is 900,what is the divisor?

Answer 1

Answer:

$1) \: \frac{x}{9} = 68 \\ \\ = > x = 68 \times 9 \\ \\ = > x = 612$

๛ So the dividend is 612 .

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$2) \: \frac{130}{4} \\ \\ = 32.5$

๛ There are 32 . 5 times of 4 in 130 .

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$3) \: \frac{261}{5} \\ \\ remainder = 1$

๛ Remainder would be 1 .

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$4) \: \frac{625}{10} \\ \\ remainder = 5$

๛ Remainder would be 5 .

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$5) \: \frac{900}{x} = 30 \\ \\ = > 30x = 900 \\ \\ = > x = \frac{900}{30} \\ \\ = > x = \frac{90}{3} \\ \\ = > x = 30$

๛ Divisor is 30 .

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Answer 2

Given :   The quotient is 68. The divisor is 9.

To Find :   dividend

Solution:

Euclid's Division Lemma

a=bq+r

a = dividend  

b = divisor

q = quotient

r = remainder

0 ≤ r < b

dividend  = divisor * quotient

=>  dividend  = 9 * 68

=>  dividend  = 612

2.how many 4's are there in 130

130 = 4 * 32  +  2

32 complete 4 and    then 1/2  4

Hence 32.5

3.what will be the remainder if 261 is divided by 5?

261 = 5 * 52 + 1

Remainder = 1

4.in 625 divide 10, what is the remainder?

625 = 10 * 62 + 5

Remainder = 5

5.the quotient is 30, the dividend is 900,what is the divisor?

divisor = 900/30  = 30

Divisor = 30

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