Question

1 )
The range of solutions for x such that a +bx – 4x? >0 is -0.5 of a and of b, where a and b are real numbers.

Answer 1

Answer:

quadratic equation is in the form ax2 +bx +c =0

– To find the nature of roots, first find determinant “D”

– D = b2 – 4ac

– If D > 0, equation has real and distinct roots

– If D < 0, equation has no real roots

– If D = 0, equation has 1 root