Math, asked by anuragvarma258, 2 months ago

1. The ratio of the present age
of father to that of son is 7:2.
After 10 years their ages will be
in the ratio of 9:4. The present
ages of the father is * 9th standard

Answers

Answered by Anonymous
3

Answer:

let ages of father and son be 7x and 2x

after 10 years

age of father = 7x + 10

age of son = 2x + 10

7x+10/2x+10 = 9/4

4(7x+10) = 9(2x+10)

28x+40 = 18x+90

10x = 50

x = 5

present age of father = 7×5 = 35years

hope it helped u

Answered by adityarajsinhgohil99
0

Answer:

answer is 35

Step-by-step explanation:

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