Question

1)The reciprocal of cotθ is​

2)Sin^2θ.cosec^2θ is

3) cot A.sinA=

Answer this question correctly
no copy ,past or me gone report​

Answer 1

Step-by-step explanation:

1. 1/ cot θ = 1/(cosθ /sinθ )

=sin θ / cos θ = tan θ

2. 1 / sin^2 θ × cosec ^2 θ = 1 / (sin ^2 θ × 1 / sin ^2 θ)

sin ^² θ and sin ^2θ gets canceled so ans = 1

3. 1 / (cot A × sin A)

= 1 / ( cos A / Sin A × Sin A)

Sin A and sin A get canceled

= 1 / cos A = sec A