1.) The refractive index of a certain substance is 1.5. Find the speed of light in this
medium. Given that the speed of light in air is 3 10 m/s.
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Answer:
we know that refractive index
n=
speedoflightinmedium
speedoflightinvacuum
where
c=
3×
10
8
m/s
1.5=
v
c
v=
1.5
3×10
8
v= 2× 10
8
m/s
For critical angle we will use snell's law
C is critical angle
n
air
=
1
n
glass
sinC= n
air
sin90
sinC=
n
glass
1
=
1.5
1
C=41.8
o
Explanation:
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