Math, asked by nithya135, 11 months ago

1.
The separate equations of the lines 6x2 + 5xy -6y2 = 0 are
1) 2x-3y=0; 3x+2y=0
2) 2x+3y=0; 3x-2y=0
3) 2x-3y=0; 3x-2y=0
4) 3x+2y=0; 2x+3y=0​

Answers

Answered by ferozemulani
12

Answer:

option 2 is correct

simply multiply the two equations, we will get the required eqn

Step-by-step explanation:

(2x+3y)*(3x-2y)

= 6x^2 - 4xy + 9xy -6y^2

= 6x^2 + 5xy - 6y^2

Answered by pratyushdas85
7

Answer:

option 2 is correct . simply addit

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