1. The side of a rhombus is 7.2 cm, and its altitude is 5 cm. Find its area.
2. The adjacent sides of a parallelogram are 36 cm and 27 cm in length. If the perpendicular distance between the shorter sides is 12 cm, find the distance between the longer sides.
Answers
Answer:
Given: parllelogram ABCD circumscribe a circle
To prove: we know that pain syndrome from the extent part are equal in length.
AP=AS-------1
BP=BQ-------2
CR=CQ-------3
DR=DS-------4
Adding 1,2,3 and 4
AP+BP+CR+DR=AS+BQ+CQ+DS
AB+CD=AD+BC-------5
ABCD is a parllelogram
AB=CD
----------6
AD=BC
From 3 and 6 we get
AB+AB=AD+AD
2AB=2AD
AB=AD
If adjacent sides of parllelogram are equal then it becomes rhombus.
Hence ABCD is a Rhombus.
Answer:
0.7 cm rhombuis 4.8 m 43 od the missing measures : (1) Area of Igm (ii) Area of |gm ABCD = 48 cm? PQRS = 252 cm DE = 6 cm PQ = 9 cm AB= ? A P 36 OT E B RT = ? the side of a rhombus is 7.2 cm, and its altitude is 5 cm. Find its area. a parallelogram with all its sides equal, the formula for area of agm is applicable to it also.] he adjacent sides of a parallelogram are 36 cm and 27 cm in length. If the perpendicularista tween the shorter sides is 12 cm, find the distance between the longer sides. 5. The area of a parallelogram and a square are the same. If the perimeter of the square is 160 m and the height of the parallelogram is 20 m, find the length of the corresponding base of the parallelogram. The area of a rhombus is 42 m´. If its perimeter is 24 m, find its altitude. 1. AX and CY are heights of the parallelogram ABCD whose are What are the lengths of XA AD and CY? DX 10 9 4 cm A F - 7 cm Fig. Q.7 B Fig. Q. 8 Cream RG = 12 cm find AB.