Question

1. The side of a square field is 43 m. If Irfanruns 8 times around it, what distancewould he cover?





2.Find the breadth of a rectangle whoselength is 85 cm and perimeter is280 cm.​

Answer 1

Answer:

Q no. 2

55 cm

Step-by-step explanation:

2. solution,

given,

length (l) = 85 cm

perimeter (P) = 280 cm

breadth (b) = x

now,

p= 2(l+b)

or, 280 cm = 2(85 cm +x)

or, 280 cm = 170 cm +2x

or, 280 cm - 170 cm = 2x

or, 110 cm = 2x

or, 110 cm /2 = x

or, 55 cm = x

∴x=55cm

the breadth of the given rectangle is 55 cm

checking (optional)

LHS

2(l+b)

2(85cm+ 55 cm)

2* 140 cm

280 cm

RHS

Answer 2

Answer:

1.1376m , 2. 55cm

Step-by-step explanation:

1. Distance covered = 8 × Perimeter of square (since distance covered in 1 time is perimeter {boundary)}and 8 times is 8 × distance covered in 1 time)

Perimeter = 4 × 43m

= 172m

Distance covered = 1376m

2. Perimeter = 2(length + breadth)

280cm = 2(85cm + breadth)

85cm + breadth = 280/2

breadth = 140cm - 85cm

Breadth = 55cm