Question

1. the side of a trianglia are,16 cm,30cm,34cm its area is​

Answer 1

$\huge\bold\gray{Answer} \\ 240 \: cm {}^{2}$

$\small\bold\pink{Given,}$

• 16 cm = a
• 30 cm = b
• 34 cm = c

Let us consider these three as a,b and c

$\small\bold\blue{Solution,}$

⇒Semiperimeter = 16+30+34 ÷ 2

⇒Sum of 16, 30 and 34 is 80

⇒Now,

80 ÷ 2 = 40

⇒By using heron's,

We know that

Area of the triangle is

$\sqrt{} s(s−a)(s−b)(s−c) \: cm {}^{2}$

$\sqrt[]{} 40 (40−16) (40−30) (40−34) \: cm {}^{2}$

$\sqrt{} 40×24×10×6 \: cm {}^{2}$

$\sqrt{} 4×10×4×6×10×6 \: cm {}^{2}$

$4 \times 6 \times 10 \: cm {}^{2}$

$240 \: {cm}^{2}$