Math, asked by shagunpathak07, 9 months ago

1. The sides of a triangle are 7x2 – 7xy + 8, -4x2 + 7xy -3 and x2 -8xy +5. Find the perimeter of the triangle. 2. Subtract b (b2 +b -7) + 5 from 3b2 – 8 and find the value of expression obtained for b = -3. 3. Find the sum of the squares of 3x, -4x and 2y 4. Find the product of the following. i) –5a2bc, 6ab, 8abc2 ii) –3x2y and (5y – xy) iii) x2y2z2 and (xy – yz + zx) iv) (p + 6) and (q – 7) v) (2x + 7) and (x2 – 5x + 6) vii) (x + y + 5) and (2x – 2y – 3) 5. The base of a parallelogram is (2x + 3) units and the corresponding height is (3x – 2) units. Find the area of the parallelogram in terms of x. What will be the area of parallelogram if x = 30 units? 6. Simplify: i) (a + b)(5a – 3b) + (a – 3b)(a – b) ii) (a – b) (a2 + b2 + ab) – (a + b) (a2 + b2 – ab) iii) (b2 – 49) (b + 7) + 343 7. Verify the following: i) (ab + bc) (ab – bc) + (bc + ca) (bc – ca) + (ca + ab) (ca – ab) = 0 ii) (a + b + c) (a2 + b2 + c2 – ab – bc – ca) = a3 + b3+ c3 – 3abc iii) (p – q) (p2 + pq + q2) = p3 – q3 Please answer it and i will mark yours as the brainliest!!!!!!

Answers

Answered by shradhakapoor2
4

Answer:

BRAINLEST!!

1.(x2-5x+6)(2x+7)

(x2-5x+6)(2x+7)=(x2)(-5x +2x)(6+7)

(x2-5x+6)(2x+7)=(x2)(-5x +2x)(6+7)=x2-3x+13

2.4x2 – 3x + 7

4x2 – 3x + 7 ⇒ 4x2 – 3x + 7x°

4x2 – 3x + 7 ⇒ 4x2 – 3x + 7x° ∵ All the exponents of x are whole numbers ∴ 4x2 – 3x + 7 is a polynomial in one variable.

3.(a - b)3 = a3 - b3 - 3ab(a - b). 5. (a + b + c)2 = a2 + b2 + c2 +2ab+2bc +2ca.

Answered by giriaishik123
1

Answer:

Step-by-step explanation: oh yeah.........................................................

BRAINLEST!!

1.(x2-5x+6)(2x+7)

(x2-5x+6)(2x+7)=(x2)(-5x +2x)(6+7)

(x2-5x+6)(2x+7)=(x2)(-5x +2x)(6+7)=x2-3x+13

2.4x2 – 3x + 7

4x2 – 3x + 7 ⇒ 4x2 – 3x + 7x°

4x2 – 3x + 7 ⇒ 4x2 – 3x + 7x° ∵ All the exponents of x are whole numbers ∴ 4x2 – 3x + 7 is a polynomial in one variable.

3.(a - b)3 = a3 - b3 - 3ab(a - b). 5. (a + b + c)2 = a2 + b2 + c2 +2ab+2bc +2ca.

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