Math, asked by arjunbanerji6307, 3 months ago

1
The simple interest on a certain sum of money for 3/2 years at 18% per annum is rupees 60 less than the simple interest on the same sum for 5/2 years at 12% per annum . find the amount

Answers

Answered by bjoshid
0

Step-by-step explanation:

• Let the sum be P.

• According to the first condition,

Sum = P

Time (T) = 2.5 years

Rate of interest (R) = 12 % p.a.

• Therefore, simple interest (S.I.) = (P × R × T) / 100

=> S.I. = (P × 12 × 2.5) / 100

Or, S.I. = 0.3 P

• According to the second condition,

Sum = P

Time (T') = 3.5 years

Rate (R') = 10 % p.a.

• Therefore, simple interest (S.I.') = (P × R' × T') / 100

=> S.I.' = ( P × 10 × 3.5 ) / 100

=> S.I.' = 0.35 P

• According to the question,

S.I.' - S.I. = 40

=> 0.35 P - 0.3 P = 40

=> 0.05 P = 40

=> P = 40 / 0.05

=> P = 800

• Therefore, sum = P = Rs. 800

Answered by ajathashathru
1

Answer:

Rs.2000/- is the Sum

Step-by-step explanation:

Let the Sum = x

S.I for the second instance = x * 5/2 *12/100 = x * 3/10

SI for the first instance = x * 3/2 * 18/100 = x * 27/100

as per given condition

= (x * 3/10) - ( x * 27/100) = 60

30x - 27x = 60 * 100

3x = 6000

x = 6000/3 = Rs.2000/-

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