Question

1
The singular points of F(z)=1/z(z-1)^2
(a) 0 1:41
3(2-1)
(c) 1,-1
(ъ) 0, 1, 1
(d) None of these​

Answer 1

Answer:

c

Step-by-step explanation:

I calculated and I said my perfect answer

Answer 2

Answer:

1,1 is the singular point of the function.

Step-by-step explanation:

A Singular point is a point where the entire function becomes 0.

$F(z) = 0\\\frac{1}{z}(z-1)^2 = 0$

$\frac{1}{z} \neq 0$  

$(z-1)^2 = z^2 - 2z +1 = 0\\= z^2 - z-z+1 = 0\\= z(z-1) - (z-1)\\z=1,1$

So the singular point is z=1,1