Question

1. The sixth term of a GS is 192 and its eleventh
term is 6144. Which term of the series is
49152?​

Answer 1

Answer:

Step-by-step explanation:

an​=arn−1

a3​=ar2=24...(1)

a6​=ar5=192...(2)

dividing (2)  by (1)  we get

ar2ar5​=24192​

r3=8⇒r=2

From (1)

ar2=24

a=2224​=6

∴a10​=(6)(2)10−1=3072

Answer 2

Step-by-step explanation:

If (2,0) is solution of equation x−2y=4, then it must satisfy the equation.

Therefore,

2−2×0=2=4

Hence (2,0) is not a solution of equation x−2y=4.